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<p>H<sub>2</sub>O<sub>2</sub> কে MnO<sub>4</sub>—দ্বারা জারণ করা হলে কোষ বিভব, E<sup>ϕ</sup>cell হিসাব কর । অর্ধ-বিক্রিয়াগুলো হল</p><p>2H<sup>+</sup> +O<sub>2</sub>+2e<sup>-</sup> ↔ H<sub>2</sub>O<sub>2</sub> ; E<sup>ϕ</sup> = +0.68 V</p><p>MnO4<sup>-</sup> + 8H<sup>+</sup> + 5e ↔ Mn<sup>2</sup>+ + 4H<sub>2</sub>O ; E<sup>ϕ</sup> = + 1.51 V <sup>-</sup></p>
A
<p> E<sup>ϕ</sup>cell = +2.19 V</p>
B
<p>E<sup>ϕ</sup>cell = +0.38 V </p>
C
<p>E<sup>ϕ</sup>cell = +0.83 V </p>
D
<p>E<sup>ϕ</sup>cell = -0.83V </p>
Answer: C - <p>E<sup>ϕ</sup>cell = +0.83 V </p>
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