Question: 
∫tan(sin-1x)1-x2dx=?
ln/tan(sin-1x)|+c
ln/|sec(sin-1x)|+c
sec2(sin-1X)+c
ln/|sec(sin-1x)|+c
Answer: 
ln/|sec(sin-1x)|+c
Last Updated: 
18/09/2020 - 08:00